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136910545153 = 203967145927
BaseRepresentation
bin111111110000010000…
…0010010000100000001
3111002101112100022102121
41333200200102010001
54220343044421103
6142521300044241
712614525301214
oct1774040220401
9432345308377
10136910545153
1153077484a78
122264b093681
13cbab7b99c5
1468ab1bb77b
1538648ac6bd
hex1fe0812101

136910545153 has 4 divisors (see below), whose sum is σ = 136977693120. Its totient is φ = 136843397188.

The previous prime is 136910545151. The next prime is 136910545183. The reversal of 136910545153 is 351545019631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 136910545153 - 21 = 136910545151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136910545151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33570925 + ... + 33575002.

It is an arithmetic number, because the mean of its divisors is an integer number (34244423280).

Almost surely, 2136910545153 is an apocalyptic number.

It is an amenable number.

136910545153 is a deficient number, since it is larger than the sum of its proper divisors (67147967).

136910545153 is an equidigital number, since it uses as much as digits as its factorization.

136910545153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67147966.

The product of its (nonzero) digits is 243000, while the sum is 43.

The spelling of 136910545153 in words is "one hundred thirty-six billion, nine hundred ten million, five hundred forty-five thousand, one hundred fifty-three".

Divisors: 1 2039 67145927 136910545153