Base | Representation |
---|---|
bin | 110100001111… |
… | …010001000111 |
3 | 221202201200001 |
4 | 310033101013 |
5 | 12001202043 |
6 | 1205302131 |
7 | 224253160 |
oct | 64172107 |
9 | 27681601 |
10 | 13694023 |
11 | 7803582 |
12 | 4704947 |
13 | 2ab6095 |
14 | 1b66767 |
15 | 130774d |
hex | d0f447 |
13694023 has 4 divisors (see below), whose sum is σ = 15650320. Its totient is φ = 11737728.
The previous prime is 13694017. The next prime is 13694047. The reversal of 13694023 is 32049631.
13694023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32049631 = 2099 ⋅15269.
It is a cyclic number.
It is not a de Polignac number, because 13694023 - 25 = 13693991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13693982 and 13694000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13694053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 978138 + ... + 978151.
It is an arithmetic number, because the mean of its divisors is an integer number (3912580).
Almost surely, 213694023 is an apocalyptic number.
13694023 is a deficient number, since it is larger than the sum of its proper divisors (1956297).
13694023 is an equidigital number, since it uses as much as digits as its factorization.
13694023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1956296.
The product of its (nonzero) digits is 3888, while the sum is 28.
The square root of 13694023 is about 3700.5436087148. The cubic root of 13694023 is about 239.2454484899.
The spelling of 13694023 in words is "thirteen million, six hundred ninety-four thousand, twenty-three".
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