Base | Representation |
---|---|
bin | 111111110001111010… |
… | …1111111111110111101 |
3 | 111002112102202122221212 |
4 | 1333203311333332331 |
5 | 4221001420214132 |
6 | 142531020534205 |
7 | 12616105430552 |
oct | 1774365777675 |
9 | 432472678855 |
10 | 136966569917 |
11 | 530a6070231 |
12 | 226659b1365 |
13 | cbba2a4458 |
14 | 68b4802a29 |
15 | 38697775b2 |
hex | 1fe3d7ffbd |
136966569917 has 2 divisors, whose sum is σ = 136966569918. Its totient is φ = 136966569916.
The previous prime is 136966569863. The next prime is 136966569923. The reversal of 136966569917 is 719965669631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130007840356 + 6958729561 = 360566^2 + 83419^2 .
It is a cyclic number.
It is not a de Polignac number, because 136966569917 - 214 = 136966553533 is a prime.
It is a super-3 number, since 3×1369665699173 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136966569937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68483284958 + 68483284959.
It is an arithmetic number, because the mean of its divisors is an integer number (68483284959).
Almost surely, 2136966569917 is an apocalyptic number.
It is an amenable number.
136966569917 is a deficient number, since it is larger than the sum of its proper divisors (1).
136966569917 is an equidigital number, since it uses as much as digits as its factorization.
136966569917 is an evil number, because the sum of its binary digits is even.
The product of its digits is 99202320, while the sum is 68.
The spelling of 136966569917 in words is "one hundred thirty-six billion, nine hundred sixty-six million, five hundred sixty-nine thousand, nine hundred seventeen".
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