Base | Representation |
---|---|
bin | 111111110010001100… |
… | …1001101010100001011 |
3 | 111002120002010120122121 |
4 | 1333210121031110023 |
5 | 4221011301041223 |
6 | 142531550432111 |
7 | 12616250041261 |
oct | 1774431152413 |
9 | 432502116577 |
10 | 136975799563 |
11 | 531002a4639 |
12 | 22668b02637 |
13 | cbbc186495 |
14 | 68b5b26431 |
15 | 386a49c15d |
hex | 1fe464d50b |
136975799563 has 2 divisors, whose sum is σ = 136975799564. Its totient is φ = 136975799562.
The previous prime is 136975799497. The next prime is 136975799629. The reversal of 136975799563 is 365997579631.
It is a balanced prime because it is at equal distance from previous prime (136975799497) and next prime (136975799629).
It is an emirp because it is prime and its reverse (365997579631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136975799563 - 213 = 136975791371 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136975799492 and 136975799501.
It is not a weakly prime, because it can be changed into another prime (136975799663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68487899781 + 68487899782.
It is an arithmetic number, because the mean of its divisors is an integer number (68487899782).
Almost surely, 2136975799563 is an apocalyptic number.
136975799563 is a deficient number, since it is larger than the sum of its proper divisors (1).
136975799563 is an equidigital number, since it uses as much as digits as its factorization.
136975799563 is an evil number, because the sum of its binary digits is even.
The product of its digits is 289340100, while the sum is 70.
The spelling of 136975799563 in words is "one hundred thirty-six billion, nine hundred seventy-five million, seven hundred ninety-nine thousand, five hundred sixty-three".
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