137004080053 has 4 divisors (see below), whose sum is σ = 137038309408. Its totient is φ = 136969850700.

The previous prime is 137004080029. The next prime is 137004080077. The reversal of 137004080053 is 350080400731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (137004080029) and next prime (137004080077).

It is a cyclic number.

It is not a de Polignac number, because 137004080053 - 2⁵ = 137004080021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 137004079997 and 137004080024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (137004080153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17108673 + ... + 17116678.

It is an arithmetic number, because the mean of its divisors is an integer number (34259577352).

Almost surely, 2^137004080053 is an apocalyptic number.

It is an amenable number.

137004080053 is a deficient number, since it is larger than the sum of its proper divisors (34229355).

137004080053 is an equidigital number, since it uses as much as digits as its factorization.

137004080053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34229354.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 137004080053 its reverse (350080400731), we get a palindrome (487084480784).

The spelling of 137004080053 in words is "one hundred thirty-seven billion, four million, eighty thousand, fifty-three".