Base | Representation |
---|---|
bin | 10011111011111110111… |
… | …110100001011110100111 |
3 | 11211222102001100101010021 |
4 | 103323332332201132213 |
5 | 134421404303344142 |
6 | 2525223241340011 |
7 | 200661536530033 |
oct | 23737676413647 |
9 | 4758361311107 |
10 | 1370077403047 |
11 | 489056a81321 |
12 | 1a1644197607 |
13 | 9c2755a30c2 |
14 | 4a45258d1c3 |
15 | 2598b225267 |
hex | 13efefa17a7 |
1370077403047 has 2 divisors, whose sum is σ = 1370077403048. Its totient is φ = 1370077403046.
The previous prime is 1370077403011. The next prime is 1370077403081. The reversal of 1370077403047 is 7403047700731.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1370077403047 is a prime.
It is a super-2 number, since 2×13700774030472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1370077402994 and 1370077403012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1370077443047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685038701523 + 685038701524.
It is an arithmetic number, because the mean of its divisors is an integer number (685038701524).
Almost surely, 21370077403047 is an apocalyptic number.
1370077403047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370077403047 is an equidigital number, since it uses as much as digits as its factorization.
1370077403047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345744, while the sum is 43.
The spelling of 1370077403047 in words is "one trillion, three hundred seventy billion, seventy-seven million, four hundred three thousand, forty-seven".
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