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1370090255141 is a prime number
BaseRepresentation
bin10011111011111111101…
…111100011001100100101
311211222102221112022212202
4103323333233203030211
5134421421101131031
62525224421024245
7200662054005506
oct23737757431445
94758387468782
101370090255141
1148906325a293
121a1648555085
139c278152baa
144a454176bad
152598c4132cb
hex13effbe3325

1370090255141 has 2 divisors, whose sum is σ = 1370090255142. Its totient is φ = 1370090255140.

The previous prime is 1370090255057. The next prime is 1370090255231. The reversal of 1370090255141 is 1415520900731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1137520370116 + 232569885025 = 1066546^2 + 482255^2 .

It is a cyclic number.

It is not a de Polignac number, because 1370090255141 - 214 = 1370090238757 is a prime.

It is a super-3 number, since 3×13700902551413 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1370090255095 and 1370090255104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1370090255041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685045127570 + 685045127571.

It is an arithmetic number, because the mean of its divisors is an integer number (685045127571).

Almost surely, 21370090255141 is an apocalyptic number.

It is an amenable number.

1370090255141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1370090255141 is an equidigital number, since it uses as much as digits as its factorization.

1370090255141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 37800, while the sum is 38.

The spelling of 1370090255141 in words is "one trillion, three hundred seventy billion, ninety million, two hundred fifty-five thousand, one hundred forty-one".