Base | Representation |
---|---|
bin | 111111110101111101… |
… | …1100101000101100111 |
3 | 111002212220001221111211 |
4 | 1333223323211011213 |
5 | 4221241134002333 |
6 | 142552305012251 |
7 | 12622343620402 |
oct | 1775373450547 |
9 | 432786057454 |
10 | 137102250343 |
11 | 53165711a13 |
12 | 226a3324087 |
13 | cc0c42b626 |
14 | 68c8840d39 |
15 | 3876628ecd |
hex | 1febee5167 |
137102250343 has 2 divisors, whose sum is σ = 137102250344. Its totient is φ = 137102250342.
The previous prime is 137102250331. The next prime is 137102250349. The reversal of 137102250343 is 343052201731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 137102250343 - 233 = 128512315751 is a prime.
It is a super-2 number, since 2×1371022503432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (137102250349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68551125171 + 68551125172.
It is an arithmetic number, because the mean of its divisors is an integer number (68551125172).
Almost surely, 2137102250343 is an apocalyptic number.
137102250343 is a deficient number, since it is larger than the sum of its proper divisors (1).
137102250343 is an equidigital number, since it uses as much as digits as its factorization.
137102250343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
The spelling of 137102250343 in words is "one hundred thirty-seven billion, one hundred two million, two hundred fifty thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •