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137252860364881 is a prime number
BaseRepresentation
bin11111001101010010101011…
…111111001000100001010001
3122222222020121211100201020101
4133031102223333020201101
5120442222324223134011
61203525032114412401
740624122554463652
oct3715225377104121
9588866554321211
10137252860364881
113a80767a557238
1213488635291101
135b77b737439a1
1425c7106a61529
1510d03ddc722c1
hex7cd4abfc8851

137252860364881 has 2 divisors, whose sum is σ = 137252860364882. Its totient is φ = 137252860364880.

The previous prime is 137252860364839. The next prime is 137252860364899. The reversal of 137252860364881 is 188463068252731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126156026886400 + 11096833478481 = 11231920^2 + 3331191^2 .

It is a cyclic number.

It is not a de Polignac number, because 137252860364881 - 29 = 137252860364369 is a prime.

It is a super-2 number, since 2×1372528603648812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (137252860334881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68626430182440 + 68626430182441.

It is an arithmetic number, because the mean of its divisors is an integer number (68626430182441).

Almost surely, 2137252860364881 is an apocalyptic number.

It is an amenable number.

137252860364881 is a deficient number, since it is larger than the sum of its proper divisors (1).

137252860364881 is an equidigital number, since it uses as much as digits as its factorization.

137252860364881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 92897280, while the sum is 64.

The spelling of 137252860364881 in words is "one hundred thirty-seven trillion, two hundred fifty-two billion, eight hundred sixty million, three hundred sixty-four thousand, eight hundred eighty-one".