Base | Representation |
---|---|
bin | 11111001101010010101011… |
… | …111111001000100000100111 |
3 | 122222222020121211100201011211 |
4 | 133031102223333020200213 |
5 | 120442222324223133324 |
6 | 1203525032114412251 |
7 | 40624122554463562 |
oct | 3715225377104047 |
9 | 588866554321154 |
10 | 137252860364839 |
11 | 3a80767a5571aa |
12 | 13488635291087 |
13 | 5b77b7374396b |
14 | 25c7106a614d9 |
15 | 10d03ddc72294 |
hex | 7cd4abfc8827 |
137252860364839 has 2 divisors, whose sum is σ = 137252860364840. Its totient is φ = 137252860364838.
The previous prime is 137252860364803. The next prime is 137252860364881. The reversal of 137252860364839 is 938463068252731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 137252860364839 - 221 = 137252858267687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (137252860364899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68626430182419 + 68626430182420.
It is an arithmetic number, because the mean of its divisors is an integer number (68626430182420).
It is a 1-persistent number, because it is pandigital, but 2⋅137252860364839 = 274505720729678 is not.
Almost surely, 2137252860364839 is an apocalyptic number.
137252860364839 is a deficient number, since it is larger than the sum of its proper divisors (1).
137252860364839 is an equidigital number, since it uses as much as digits as its factorization.
137252860364839 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 313528320, while the sum is 67.
The spelling of 137252860364839 in words is "one hundred thirty-seven trillion, two hundred fifty-two billion, eight hundred sixty million, three hundred sixty-four thousand, eight hundred thirty-nine".
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