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1372537948253 is a prime number
BaseRepresentation
bin10011111110010001101…
…000110000100001011101
311212012202112022000121012
4103332101220300201131
5134441424203321003
62530311335345005
7201106525031153
oct23762150604135
94765675260535
101372537948253
1148a0a998735a
121a2010222165
139c578299c04
144a60728d3d3
1525a8225a8d8
hex13f91a3085d

1372537948253 has 2 divisors, whose sum is σ = 1372537948254. Its totient is φ = 1372537948252.

The previous prime is 1372537948217. The next prime is 1372537948343. The reversal of 1372537948253 is 3528497352731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 737053156324 + 635484791929 = 858518^2 + 797173^2 .

It is a cyclic number.

It is not a de Polignac number, because 1372537948253 - 216 = 1372537882717 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1372537948192 and 1372537948201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1372537941253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 686268974126 + 686268974127.

It is an arithmetic number, because the mean of its divisors is an integer number (686268974127).

Almost surely, 21372537948253 is an apocalyptic number.

It is an amenable number.

1372537948253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1372537948253 is an equidigital number, since it uses as much as digits as its factorization.

1372537948253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38102400, while the sum is 59.

The spelling of 1372537948253 in words is "one trillion, three hundred seventy-two billion, five hundred thirty-seven million, nine hundred forty-eight thousand, two hundred fifty-three".