Base | Representation |
---|---|
bin | 111111111010101011… |
… | …0110101010100001111 |
3 | 111010021220122020212002 |
4 | 1333311112311110033 |
5 | 4222102124432042 |
6 | 143020114302515 |
7 | 12626304030053 |
oct | 1776526652417 |
9 | 433256566762 |
10 | 137260389647 |
11 | 53236a03357 |
12 | 22728287a3b |
13 | cc3611a194 |
14 | 6901847c63 |
15 | 3885465132 |
hex | 1ff55b550f |
137260389647 has 2 divisors, whose sum is σ = 137260389648. Its totient is φ = 137260389646.
The previous prime is 137260389559. The next prime is 137260389683. The reversal of 137260389647 is 746983062731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 137260389647 - 212 = 137260385551 is a prime.
It is a super-3 number, since 3×1372603896473 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 137260389592 and 137260389601.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (137260089647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68630194823 + 68630194824.
It is an arithmetic number, because the mean of its divisors is an integer number (68630194824).
Almost surely, 2137260389647 is an apocalyptic number.
137260389647 is a deficient number, since it is larger than the sum of its proper divisors (1).
137260389647 is an equidigital number, since it uses as much as digits as its factorization.
137260389647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9144576, while the sum is 56.
The spelling of 137260389647 in words is "one hundred thirty-seven billion, two hundred sixty million, three hundred eighty-nine thousand, six hundred forty-seven".
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