Base | Representation |
---|---|
bin | 10011111110111001110… |
… | …010000011100001010101 |
3 | 11212021111110122200020102 |
4 | 103332321302003201111 |
5 | 134444314114132010 |
6 | 2530502235343445 |
7 | 201132313640120 |
oct | 23767162034125 |
9 | 4767443580212 |
10 | 1373211474005 |
11 | 48a415094208 |
12 | 1a21798b1b85 |
13 | 9c65499a067 |
14 | 4a66c8d53b7 |
15 | 25ac144dba5 |
hex | 13fb9c83855 |
1373211474005 has 16 divisors (see below), whose sum is σ = 1883287591680. Its totient is φ = 941617654272.
The previous prime is 1373211474001. The next prime is 1373211474023. The reversal of 1373211474005 is 5004741123731.
It is a cyclic number.
It is not a de Polignac number, because 1373211474005 - 22 = 1373211474001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1373211474005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1373211474001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2761061 + ... + 3220229.
It is an arithmetic number, because the mean of its divisors is an integer number (117705474480).
Almost surely, 21373211474005 is an apocalyptic number.
It is an amenable number.
1373211474005 is a deficient number, since it is larger than the sum of its proper divisors (510076117675).
1373211474005 is an equidigital number, since it uses as much as digits as its factorization.
1373211474005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 544628.
The product of its (nonzero) digits is 70560, while the sum is 38.
Adding to 1373211474005 its reverse (5004741123731), we get a palindrome (6377952597736).
The spelling of 1373211474005 in words is "one trillion, three hundred seventy-three billion, two hundred eleven million, four hundred seventy-four thousand, five".
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