13740400151 has 4 divisors (see below), whose sum is σ = 14075531904. Its totient is φ = 13405268400.

The previous prime is 13740400147. The next prime is 13740400159. The reversal of 13740400151 is 15100404731.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15100404731 = 10243 ⋅1474217.

It is a cyclic number.

It is not a de Polignac number, because 13740400151 - 2² = 13740400147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13740400151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13740400159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167565815 + ... + 167565896.

It is an arithmetic number, because the mean of its divisors is an integer number (3518882976).

Almost surely, 2^13740400151 is an apocalyptic number.

13740400151 is a deficient number, since it is larger than the sum of its proper divisors (335131753).

13740400151 is an equidigital number, since it uses as much as digits as its factorization.

13740400151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335131752.

The product of its (nonzero) digits is 1680, while the sum is 26.

Adding to 13740400151 its reverse (15100404731), we get a palindrome (28840804882).

The spelling of 13740400151 in words is "thirteen billion, seven hundred forty million, four hundred thousand, one hundred fifty-one".