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13743103201 is a prime number
BaseRepresentation
bin11001100110010011…
…10001110011100001
31022110210001222102021
430303021301303201
5211121213300301
610151414221441
7664365310162
oct146311616341
938423058367
1013743103201
115912694933
1227b6654881
1313b0323239
14945323769
155567da8a1
hex333271ce1

13743103201 has 2 divisors, whose sum is σ = 13743103202. Its totient is φ = 13743103200.

The previous prime is 13743103183. The next prime is 13743103243. The reversal of 13743103201 is 10230134731.

13743103201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12675382225 + 1067720976 = 112585^2 + 32676^2 .

It is a cyclic number.

It is not a de Polignac number, because 13743103201 - 25 = 13743103169 is a prime.

It is not a weakly prime, because it can be changed into another prime (13743100201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6871551600 + 6871551601.

It is an arithmetic number, because the mean of its divisors is an integer number (6871551601).

Almost surely, 213743103201 is an apocalyptic number.

It is an amenable number.

13743103201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13743103201 is an equidigital number, since it uses as much as digits as its factorization.

13743103201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 13743103201 its reverse (10230134731), we get a palindrome (23973237932).

The spelling of 13743103201 in words is "thirteen billion, seven hundred forty-three million, one hundred three thousand, two hundred one".