Base | Representation |
---|---|
bin | 1000000000000000111… |
… | …0101111111101011011 |
3 | 111010202121220200011021 |
4 | 2000000032233331123 |
5 | 4222440330214211 |
6 | 143050152343311 |
7 | 12633650456554 |
oct | 2000016577533 |
9 | 433677820137 |
10 | 137442819931 |
11 | 5331a98598a |
12 | 227793a4b37 |
13 | cc64b622b1 |
14 | 691bb7532b |
15 | 389649d771 |
hex | 20003aff5b |
137442819931 has 2 divisors, whose sum is σ = 137442819932. Its totient is φ = 137442819930.
The previous prime is 137442819929. The next prime is 137442819947. The reversal of 137442819931 is 139918244731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 137442819931 - 21 = 137442819929 is a prime.
It is a super-2 number, since 2×1374428199312 (a number of 23 digits) contains 22 as substring.
Together with 137442819929, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (137442810931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68721409965 + 68721409966.
It is an arithmetic number, because the mean of its divisors is an integer number (68721409966).
Almost surely, 2137442819931 is an apocalyptic number.
137442819931 is a deficient number, since it is larger than the sum of its proper divisors (1).
137442819931 is an equidigital number, since it uses as much as digits as its factorization.
137442819931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1306368, while the sum is 52.
The spelling of 137442819931 in words is "one hundred thirty-seven billion, four hundred forty-two million, eight hundred nineteen thousand, nine hundred thirty-one".
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