Base | Representation |
---|---|
bin | 1100100000000011000101… |
… | …1001111000110011010100 |
3 | 1210122222112110111112222112 |
4 | 3020000301121320303110 |
5 | 3300143143344421134 |
6 | 45122123353050152 |
7 | 2616011036115302 |
oct | 310006131706324 |
9 | 53588473445875 |
10 | 13744724217044 |
11 | 441a117550637 |
12 | 165b9a03b6958 |
13 | 789177b673c2 |
14 | 3573690cb272 |
15 | 18c7e9d541ce |
hex | c8031678cd4 |
13744724217044 has 6 divisors (see below), whose sum is σ = 24053267379834. Its totient is φ = 6872362108520.
The previous prime is 13744724216963. The next prime is 13744724217067. The reversal of 13744724217044 is 44071242744731.
It can be written as a sum of positive squares in only one way, i.e., 13723038709444 + 21685507600 = 3704462^2 + 147260^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13744724216983 and 13744724217001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1718090527127 + ... + 1718090527134.
It is an arithmetic number, because the mean of its divisors is an integer number (4008877896639).
Almost surely, 213744724217044 is an apocalyptic number.
It is an amenable number.
13744724217044 is a deficient number, since it is larger than the sum of its proper divisors (10308543162790).
13744724217044 is a wasteful number, since it uses less digits than its factorization.
13744724217044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3436181054265 (or 3436181054263 counting only the distinct ones).
The product of its (nonzero) digits is 4214784, while the sum is 50.
The spelling of 13744724217044 in words is "thirteen trillion, seven hundred forty-four billion, seven hundred twenty-four million, two hundred seventeen thousand, forty-four".
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