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13749000211 = 39521347891
BaseRepresentation
bin11001100111000000…
…10001100000010011
31022111012011120121001
430303200101200103
5211124221001321
610152144442431
7664466400502
oct146340214023
938435146531
1013749000211
115915a523a1
1227b8619417
1313b16093ab
1494601a839
155570a2c91
hex333811813

13749000211 has 4 divisors (see below), whose sum is σ = 13749387624. Its totient is φ = 13748612800.

The previous prime is 13749000197. The next prime is 13749000233. The reversal of 13749000211 is 11200094731.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13749000211 - 25 = 13749000179 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13749000211.

It is not an unprimeable number, because it can be changed into a prime (13749000271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134425 + ... + 213466.

It is an arithmetic number, because the mean of its divisors is an integer number (3437346906).

Almost surely, 213749000211 is an apocalyptic number.

13749000211 is a deficient number, since it is larger than the sum of its proper divisors (387413).

13749000211 is an equidigital number, since it uses as much as digits as its factorization.

13749000211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 387412.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 13749000211 its reverse (11200094731), we get a palindrome (24949094942).

The spelling of 13749000211 in words is "thirteen billion, seven hundred forty-nine million, two hundred eleven", and thus it is an aban number.

Divisors: 1 39521 347891 13749000211