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1375075013141 is a prime number
BaseRepresentation
bin10100000000101000110…
…110111001001000010101
311212110022100020021100102
4110000220312321020111
5140012123200410031
62531411205423445
7201226432521614
oct24005066711025
94773270207312
101375075013141
11490190aa67a5
121a25b9a0ab85
139c890aa5c3b
144a7a81cb87b
1525b7ed587cb
hex14028db9215

1375075013141 has 2 divisors, whose sum is σ = 1375075013142. Its totient is φ = 1375075013140.

The previous prime is 1375075013021. The next prime is 1375075013227. The reversal of 1375075013141 is 1413105705731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1210506052900 + 164568960241 = 1100230^2 + 405671^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1375075013141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1375075013095 and 1375075013104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1375075013941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 687537506570 + 687537506571.

It is an arithmetic number, because the mean of its divisors is an integer number (687537506571).

Almost surely, 21375075013141 is an apocalyptic number.

It is an amenable number.

1375075013141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1375075013141 is an equidigital number, since it uses as much as digits as its factorization.

1375075013141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 44100, while the sum is 38.

The spelling of 1375075013141 in words is "one trillion, three hundred seventy-five billion, seventy-five million, thirteen thousand, one hundred forty-one".