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137544302141 = 1257111094131
BaseRepresentation
bin1000000000011001000…
…1110111111000111101
3111011000200212111120122
42000012101313320331
54223142320132031
6143104215424325
712636322164221
oct2000621677075
9434020774518
10137544302141
1153372199a84
12227a73850a5
13cc7cba463c
14692b430781
1538a034747b
hex2006477e3d

137544302141 has 4 divisors (see below), whose sum is σ = 137545521984. Its totient is φ = 137543082300.

The previous prime is 137544302131. The next prime is 137544302149. The reversal of 137544302141 is 141203445731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-137544302141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (137544302149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 421355 + ... + 672776.

It is an arithmetic number, because the mean of its divisors is an integer number (34386380496).

Almost surely, 2137544302141 is an apocalyptic number.

It is an amenable number.

137544302141 is a deficient number, since it is larger than the sum of its proper divisors (1219843).

137544302141 is a wasteful number, since it uses less digits than its factorization.

137544302141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1219842.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 137544302141 its reverse (141203445731), we get a palindrome (278747747872).

The spelling of 137544302141 in words is "one hundred thirty-seven billion, five hundred forty-four million, three hundred two thousand, one hundred forty-one".

Divisors: 1 125711 1094131 137544302141