Base | Representation |
---|---|
bin | 10100000001110111111… |
… | …111110011101010111101 |
3 | 11212120201212121022002212 |
4 | 110001313333303222331 |
5 | 140022333101001031 |
6 | 2532151035430205 |
7 | 201304354224146 |
oct | 24016777635275 |
9 | 4776655538085 |
10 | 1376402750141 |
11 | 490802519201 |
12 | 1a290a5b5365 |
13 | 9ca42ba2b33 |
14 | 4a89268cacd |
15 | 25c0b6c712b |
hex | 14077ff3abd |
1376402750141 has 2 divisors, whose sum is σ = 1376402750142. Its totient is φ = 1376402750140.
The previous prime is 1376402750123. The next prime is 1376402750147. The reversal of 1376402750141 is 1410572046731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1305089184025 + 71313566116 = 1142405^2 + 267046^2 .
It is a cyclic number.
It is not a de Polignac number, because 1376402750141 - 226 = 1376335641277 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1376402750147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688201375070 + 688201375071.
It is an arithmetic number, because the mean of its divisors is an integer number (688201375071).
Almost surely, 21376402750141 is an apocalyptic number.
It is an amenable number.
1376402750141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1376402750141 is an equidigital number, since it uses as much as digits as its factorization.
1376402750141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 41.
Adding to 1376402750141 its reverse (1410572046731), we get a palindrome (2786974796872).
The spelling of 1376402750141 in words is "one trillion, three hundred seventy-six billion, four hundred two million, seven hundred fifty thousand, one hundred forty-one".
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