Base | Representation |
---|---|
bin | 11001101000110100… |
… | …10000101101000001 |
3 | 1022112020202212112122 |
4 | 30310122100231001 |
5 | 211142113420111 |
6 | 10153450334025 |
7 | 665042531465 |
oct | 146432205501 |
9 | 38466685478 |
10 | 13764201281 |
11 | 5923595166 |
12 | 280172a315 |
13 | 13b47cc3cc |
14 | 9480564a5 |
15 | 5585a6cdb |
hex | 334690b41 |
13764201281 has 2 divisors, whose sum is σ = 13764201282. Its totient is φ = 13764201280.
The previous prime is 13764201257. The next prime is 13764201313. The reversal of 13764201281 is 18210246731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7532677681 + 6231523600 = 86791^2 + 78940^2 .
It is an emirp because it is prime and its reverse (18210246731) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13764201281 is a prime.
It is a super-2 number, since 2×137642012812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13764201211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6882100640 + 6882100641.
It is an arithmetic number, because the mean of its divisors is an integer number (6882100641).
Almost surely, 213764201281 is an apocalyptic number.
It is an amenable number.
13764201281 is a deficient number, since it is larger than the sum of its proper divisors (1).
13764201281 is an equidigital number, since it uses as much as digits as its factorization.
13764201281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 13764201281 in words is "thirteen billion, seven hundred sixty-four million, two hundred one thousand, two hundred eighty-one".
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