Base | Representation |
---|---|
bin | 10100000010101111010… |
… | …110100100111100110111 |
3 | 11212200010121010221210222 |
4 | 110002233112210330313 |
5 | 140031233323403124 |
6 | 2532423133204555 |
7 | 201336362202524 |
oct | 24025726447467 |
9 | 4780117127728 |
10 | 1377331466039 |
11 | 491139784201 |
12 | 1a2b2963075b |
13 | 9cb60411b79 |
14 | 4a93db6214b |
15 | 25c62ec725e |
hex | 140af5a4f37 |
1377331466039 has 2 divisors, whose sum is σ = 1377331466040. Its totient is φ = 1377331466038.
The previous prime is 1377331466033. The next prime is 1377331466099. The reversal of 1377331466039 is 9306641337731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1377331466039 - 216 = 1377331400503 is a prime.
It is a super-2 number, since 2×13773314660392 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1377331466033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688665733019 + 688665733020.
It is an arithmetic number, because the mean of its divisors is an integer number (688665733020).
Almost surely, 21377331466039 is an apocalyptic number.
1377331466039 is a deficient number, since it is larger than the sum of its proper divisors (1).
1377331466039 is an equidigital number, since it uses as much as digits as its factorization.
1377331466039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5143824, while the sum is 53.
The spelling of 1377331466039 in words is "one trillion, three hundred seventy-seven billion, three hundred thirty-one million, four hundred sixty-six thousand, thirty-nine".
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