Base | Representation |
---|---|
bin | 11001101010000000… |
… | …11000100110110001 |
3 | 1022112221120121111212 |
4 | 30311000120212301 |
5 | 211202143220441 |
6 | 10154444445505 |
7 | 665223504161 |
oct | 146500304661 |
9 | 38487517455 |
10 | 13774195121 |
11 | 59291a0735 |
12 | 2804b49895 |
13 | 13b68bb21b |
14 | 9494d85a1 |
15 | 5593cceeb |
hex | 3350189b1 |
13774195121 has 4 divisors (see below), whose sum is σ = 13791180144. Its totient is φ = 13757210100.
The previous prime is 13774195111. The next prime is 13774195133. The reversal of 13774195121 is 12159147731.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12159147731 = 23 ⋅528658597.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13774195121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13774195111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8491295 + ... + 8492916.
It is an arithmetic number, because the mean of its divisors is an integer number (3447795036).
Almost surely, 213774195121 is an apocalyptic number.
It is an amenable number.
13774195121 is a deficient number, since it is larger than the sum of its proper divisors (16985023).
13774195121 is an equidigital number, since it uses as much as digits as its factorization.
13774195121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16985022.
The product of its digits is 52920, while the sum is 41.
The spelling of 13774195121 in words is "thirteen billion, seven hundred seventy-four million, one hundred ninety-five thousand, one hundred twenty-one".
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