Base | Representation |
---|---|
bin | 1100100001110010110111… |
… | …0110001111100011100011 |
3 | 1210202211222120101022222121 |
4 | 3020130231312033203203 |
5 | 3301141121200444413 |
6 | 45144005010245111 |
7 | 2621122430165536 |
oct | 310345566174343 |
9 | 53684876338877 |
10 | 13774729312483 |
11 | 4430914654977 |
12 | 1665774b86797 |
13 | 78bc4a2c4849 |
14 | 3589b40a0a1d |
15 | 18d4a4137b8d |
hex | c872dd8f8e3 |
13774729312483 has 2 divisors, whose sum is σ = 13774729312484. Its totient is φ = 13774729312482.
The previous prime is 13774729312481. The next prime is 13774729312537. The reversal of 13774729312483 is 38421392747731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13774729312483 - 21 = 13774729312481 is a prime.
Together with 13774729312481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13774729312481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6887364656241 + 6887364656242.
It is an arithmetic number, because the mean of its divisors is an integer number (6887364656242).
Almost surely, 213774729312483 is an apocalyptic number.
13774729312483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13774729312483 is an equidigital number, since it uses as much as digits as its factorization.
13774729312483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42674688, while the sum is 61.
The spelling of 13774729312483 in words is "thirteen trillion, seven hundred seventy-four billion, seven hundred twenty-nine million, three hundred twelve thousand, four hundred eighty-three".
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