Base | Representation |
---|---|
bin | 11111010100110110001100… |
… | …011010100001000011001011 |
3 | 200001210212200002000212120101 |
4 | 133110312030122201003023 |
5 | 121024224100024341042 |
6 | 1205003332032110231 |
7 | 41006462063241301 |
oct | 3724661432410313 |
9 | 601725602025511 |
10 | 137772021715147 |
11 | 3a9978716047a6 |
12 | 13551183395377 |
13 | 5bb4acc5a3431 |
14 | 26042b6a20271 |
15 | 10ddb76bb26b7 |
hex | 7d4d8c6a10cb |
137772021715147 has 2 divisors, whose sum is σ = 137772021715148. Its totient is φ = 137772021715146.
The previous prime is 137772021715117. The next prime is 137772021715213. The reversal of 137772021715147 is 741517120277731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 137772021715147 - 223 = 137772013326539 is a prime.
It is a super-2 number, since 2×1377720217151472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (137772021715117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68886010857573 + 68886010857574.
It is an arithmetic number, because the mean of its divisors is an integer number (68886010857574).
Almost surely, 2137772021715147 is an apocalyptic number.
137772021715147 is a deficient number, since it is larger than the sum of its proper divisors (1).
137772021715147 is an equidigital number, since it uses as much as digits as its factorization.
137772021715147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4033680, while the sum is 55.
The spelling of 137772021715147 in words is "one hundred thirty-seven trillion, seven hundred seventy-two billion, twenty-one million, seven hundred fifteen thousand, one hundred forty-seven".
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