Base | Representation |
---|---|
bin | 1000000010000101111… |
… | …0101011101011100110 |
3 | 111012012111120010002000 |
4 | 2000201132223223212 |
5 | 4230111131113323 |
6 | 143221400430130 |
7 | 12653533061340 |
oct | 2004136535346 |
9 | 435174503060 |
10 | 138000644838 |
11 | 53586848001 |
12 | 228b4178346 |
13 | 100235b22c4 |
14 | 6971ca0290 |
15 | 38ca439e43 |
hex | 20217abae6 |
138000644838 has 32 divisors (see below), whose sum is σ = 350477829120. Its totient is φ = 39428755560.
The previous prime is 138000644819. The next prime is 138000644857. The reversal of 138000644838 is 838446000831.
It is an interprime number because it is at equal distance from previous prime (138000644819) and next prime (138000644857).
It is a super-3 number, since 3×1380006448383 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 138000644793 and 138000644802.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182540158 + ... + 182540913.
It is an arithmetic number, because the mean of its divisors is an integer number (10952432160).
Almost surely, 2138000644838 is an apocalyptic number.
138000644838 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
138000644838 is an abundant number, since it is smaller than the sum of its proper divisors (212477184282).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
138000644838 is a wasteful number, since it uses less digits than its factorization.
138000644838 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 365081089 (or 365081083 counting only the distinct ones).
The product of its (nonzero) digits is 442368, while the sum is 45.
The spelling of 138000644838 in words is "one hundred thirty-eight billion, six hundred forty-four thousand, eight hundred thirty-eight".
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