Base | Representation |
---|---|
bin | 1100100011010101001100… |
… | …0111111111111111100111 |
3 | 1210212101010002122012211010 |
4 | 3020311103013333333213 |
5 | 3302104200334344403 |
6 | 45204052111313303 |
7 | 2623045505625123 |
oct | 310652307777747 |
9 | 53771102565733 |
10 | 13801124528103 |
11 | 444102a002060 |
12 | 166a90081b833 |
13 | 7915958c2c23 |
14 | 359d99872583 |
15 | 18deeb557603 |
hex | c8d531fffe7 |
13801124528103 has 32 divisors (see below), whose sum is σ = 20103786420480. Its totient is φ = 8352065384960.
The previous prime is 13801124528099. The next prime is 13801124528141. The reversal of 13801124528103 is 30182542110831.
It is not a de Polignac number, because 13801124528103 - 22 = 13801124528099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13801124528153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 77319583 + ... + 77497871.
It is an arithmetic number, because the mean of its divisors is an integer number (628243325640).
Almost surely, 213801124528103 is an apocalyptic number.
13801124528103 is a deficient number, since it is larger than the sum of its proper divisors (6302661892377).
13801124528103 is a wasteful number, since it uses less digits than its factorization.
13801124528103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 181727.
The product of its (nonzero) digits is 46080, while the sum is 39.
Adding to 13801124528103 its reverse (30182542110831), we get a palindrome (43983666638934).
The spelling of 13801124528103 in words is "thirteen trillion, eight hundred one billion, one hundred twenty-four million, five hundred twenty-eight thousand, one hundred three".
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