Base | Representation |
---|---|
bin | 10100000101100101001… |
… | …001011011101010100111 |
3 | 11212222000011021101102022 |
4 | 110011211021123222213 |
5 | 140104010124122242 |
6 | 2534045525333355 |
7 | 201505065633434 |
oct | 24054511335247 |
9 | 4788004241368 |
10 | 1380381473447 |
11 | 49246439a989 |
12 | 1a363ab6725b |
13 | a0228284c92 |
14 | 4ab4cc64b8b |
15 | 25d90b480d2 |
hex | 1416525baa7 |
1380381473447 has 2 divisors, whose sum is σ = 1380381473448. Its totient is φ = 1380381473446.
The previous prime is 1380381473411. The next prime is 1380381473473. The reversal of 1380381473447 is 7443741830831.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1380381473447 - 240 = 280869845671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1380381473407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690190736723 + 690190736724.
It is an arithmetic number, because the mean of its divisors is an integer number (690190736724).
Almost surely, 21380381473447 is an apocalyptic number.
1380381473447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380381473447 is an equidigital number, since it uses as much as digits as its factorization.
1380381473447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5419008, while the sum is 53.
The spelling of 1380381473447 in words is "one trillion, three hundred eighty billion, three hundred eighty-one million, four hundred seventy-three thousand, four hundred forty-seven".
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