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13804832114401 is a prime number
BaseRepresentation
bin1100100011100011000000…
…0111010100011011100001
31210212201200111010010002011
43020320300013110123201
53302134244010130101
645205504033552521
72623236415606456
oct310706007243341
953781614103064
1013804832114401
114442661923569
12166b576415741
13791a36a71883
1435a22c02982d
1518e166cbb751
hexc8e301d46e1

13804832114401 has 2 divisors, whose sum is σ = 13804832114402. Its totient is φ = 13804832114400.

The previous prime is 13804832114399. The next prime is 13804832114449. The reversal of 13804832114401 is 10441123840831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11485836133776 + 2318995980625 = 3389076^2 + 1522825^2 .

It is a cyclic number.

It is not a de Polignac number, because 13804832114401 - 21 = 13804832114399 is a prime.

Together with 13804832114399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13804832114461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6902416057200 + 6902416057201.

It is an arithmetic number, because the mean of its divisors is an integer number (6902416057201).

Almost surely, 213804832114401 is an apocalyptic number.

It is an amenable number.

13804832114401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13804832114401 is an equidigital number, since it uses as much as digits as its factorization.

13804832114401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 73728, while the sum is 40.

The spelling of 13804832114401 in words is "thirteen trillion, eight hundred four billion, eight hundred thirty-two million, one hundred fourteen thousand, four hundred one".