Base | Representation |
---|---|
bin | 1100100011100011000000… |
… | …0111010100011110101001 |
3 | 1210212201200111010010100120 |
4 | 3020320300013110132221 |
5 | 3302134244010131401 |
6 | 45205504033553453 |
7 | 2623236415610163 |
oct | 310706007243651 |
9 | 53781614103316 |
10 | 13804832114601 |
11 | 4442661923730 |
12 | 166b576415889 |
13 | 791a36a719a8 |
14 | 35a22c029933 |
15 | 18e166cbb836 |
hex | c8e301d47a9 |
13804832114601 has 16 divisors (see below), whose sum is σ = 20085605008320. Its totient is φ = 8364127749120.
The previous prime is 13804832114543. The next prime is 13804832114627. The reversal of 13804832114601 is 10641123840831.
It is not a de Polignac number, because 13804832114601 - 226 = 13804765005737 is a prime.
It is a super-3 number, since 3×138048321146013 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13804832114401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60814216 + ... + 61040793.
It is an arithmetic number, because the mean of its divisors is an integer number (1255350313020).
Almost surely, 213804832114601 is an apocalyptic number.
13804832114601 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13804832114601 is a deficient number, since it is larger than the sum of its proper divisors (6280772893719).
13804832114601 is a wasteful number, since it uses less digits than its factorization.
13804832114601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121858456.
The product of its (nonzero) digits is 110592, while the sum is 42.
The spelling of 13804832114601 in words is "thirteen trillion, eight hundred four billion, eight hundred thirty-two million, one hundred fourteen thousand, six hundred one".
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