1380953451253 has 2 divisors, whose sum is σ = 1380953451254. Its totient is φ = 1380953451252.

The previous prime is 1380953451217. The next prime is 1380953451301. The reversal of 1380953451253 is 3521543590831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1268556195204 + 112397256049 = 1126302^2 + 335257^2 .

It is a cyclic number.

It is not a de Polignac number, because 1380953451253 - 2²⁹ = 1380416580341 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1380953451197 and 1380953451206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1380953451203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690476725626 + 690476725627.

It is an arithmetic number, because the mean of its divisors is an integer number (690476725627).

Almost surely, 2^{1380953451253} is an apocalyptic number.

It is an amenable number.

1380953451253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1380953451253 is an equidigital number, since it uses as much as digits as its factorization.

1380953451253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 49.

The spelling of 1380953451253 in words is "one trillion, three hundred eighty billion, nine hundred fifty-three million, four hundred fifty-one thousand, two hundred fifty-three".