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1381114619953 is a prime number
BaseRepresentation
bin10100000110010000110…
…110001010100000110001
311220000220020211002100121
4110012100312022200301
5140112010320314303
62534250355250241
7201532210400005
oct24062066124061
94800806732317
101381114619953
11492800219792
121a38045a9981
13a031412b593
144abbc38a705
1525dd51b69bd
hex14190d8a831

1381114619953 has 2 divisors, whose sum is σ = 1381114619954. Its totient is φ = 1381114619952.

The previous prime is 1381114619891. The next prime is 1381114619959. The reversal of 1381114619953 is 3599164111831.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 809681431329 + 571433188624 = 899823^2 + 755932^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1381114619953 is a prime.

It is a super-3 number, since 3×13811146199533 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1381114619953.

It is not a weakly prime, because it can be changed into another prime (1381114619959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690557309976 + 690557309977.

It is an arithmetic number, because the mean of its divisors is an integer number (690557309977).

Almost surely, 21381114619953 is an apocalyptic number.

It is an amenable number.

1381114619953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1381114619953 is an equidigital number, since it uses as much as digits as its factorization.

1381114619953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 699840, while the sum is 52.

The spelling of 1381114619953 in words is "one trillion, three hundred eighty-one billion, one hundred fourteen million, six hundred nineteen thousand, nine hundred fifty-three".