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13811280133 = 71973040019
BaseRepresentation
bin11001101110011011…
…10110100100000101
31022122112100201120211
430313031312210011
5211241141431013
610202251355421
7666153641560
oct146715664405
938575321524
1013811280133
115948120202
122815452b71
1313c14a4011
149503cd4d7
1555c7a623d
hex337376905

13811280133 has 4 divisors (see below), whose sum is σ = 15784320160. Its totient is φ = 11838240108.

The previous prime is 13811280113. The next prime is 13811280167. The reversal of 13811280133 is 33108211831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13811280133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13811280095 and 13811280104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13811280113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 986520003 + ... + 986520016.

It is an arithmetic number, because the mean of its divisors is an integer number (3946080040).

Almost surely, 213811280133 is an apocalyptic number.

It is an amenable number.

13811280133 is a deficient number, since it is larger than the sum of its proper divisors (1973040027).

13811280133 is an equidigital number, since it uses as much as digits as its factorization.

13811280133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1973040026.

The product of its (nonzero) digits is 3456, while the sum is 31.

Adding to 13811280133 its reverse (33108211831), we get a palindrome (46919491964).

The spelling of 13811280133 in words is "thirteen billion, eight hundred eleven million, two hundred eighty thousand, one hundred thirty-three".

Divisors: 1 7 1973040019 13811280133