Base | Representation |
---|---|
bin | 10100000110100101000… |
… | …100100111011001011011 |
3 | 11220001202220022222020112 |
4 | 110012211010213121123 |
5 | 140113204202440403 |
6 | 2534344200314535 |
7 | 201543500565014 |
oct | 24064504473133 |
9 | 4801686288215 |
10 | 1381453952603 |
11 | 49296481839a |
12 | 1a389a172a4b |
13 | a036951b22a |
14 | 4ac1147c00b |
15 | 25e04d949d8 |
hex | 141a512765b |
1381453952603 has 2 divisors, whose sum is σ = 1381453952604. Its totient is φ = 1381453952602.
The previous prime is 1381453952509. The next prime is 1381453952629. The reversal of 1381453952603 is 3062593541831.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3062593541831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1381453952603 - 224 = 1381437175387 is a prime.
It is not a weakly prime, because it can be changed into another prime (1381453954603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690726976301 + 690726976302.
It is an arithmetic number, because the mean of its divisors is an integer number (690726976302).
Almost surely, 21381453952603 is an apocalyptic number.
1381453952603 is a deficient number, since it is larger than the sum of its proper divisors (1).
1381453952603 is an equidigital number, since it uses as much as digits as its factorization.
1381453952603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 50.
The spelling of 1381453952603 in words is "one trillion, three hundred eighty-one billion, four hundred fifty-three million, nine hundred fifty-two thousand, six hundred three".
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