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13815040718147 is a prime number
BaseRepresentation
bin1100100100001001000010…
…0110000011010101000011
31210220201000221101220202012
43021002100212003111003
53302321200410440042
645214313031443135
72624050405401554
oct311022046032503
953821027356665
1013815040718147
114446a20367669
1216715452264ab
137929a2a394c6
1435a919b7032b
1518e563132e82
hexc9090983543

13815040718147 has 2 divisors, whose sum is σ = 13815040718148. Its totient is φ = 13815040718146.

The previous prime is 13815040718131. The next prime is 13815040718177. The reversal of 13815040718147 is 74181704051831.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13815040718147 - 24 = 13815040718131 is a prime.

It is a super-2 number, since 2×138150407181472 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13815040718095 and 13815040718104.

It is not a weakly prime, because it can be changed into another prime (13815040718107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6907520359073 + 6907520359074.

It is an arithmetic number, because the mean of its divisors is an integer number (6907520359074).

Almost surely, 213815040718147 is an apocalyptic number.

13815040718147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13815040718147 is an equidigital number, since it uses as much as digits as its factorization.

13815040718147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 752640, while the sum is 50.

Adding to 13815040718147 its reverse (74181704051831), we get a palindrome (87996744769978).

The spelling of 13815040718147 in words is "thirteen trillion, eight hundred fifteen billion, forty million, seven hundred eighteen thousand, one hundred forty-seven".