Base | Representation |
---|---|
bin | 1100100100001001000010… |
… | …0110000011010101000011 |
3 | 1210220201000221101220202012 |
4 | 3021002100212003111003 |
5 | 3302321200410440042 |
6 | 45214313031443135 |
7 | 2624050405401554 |
oct | 311022046032503 |
9 | 53821027356665 |
10 | 13815040718147 |
11 | 4446a20367669 |
12 | 16715452264ab |
13 | 7929a2a394c6 |
14 | 35a919b7032b |
15 | 18e563132e82 |
hex | c9090983543 |
13815040718147 has 2 divisors, whose sum is σ = 13815040718148. Its totient is φ = 13815040718146.
The previous prime is 13815040718131. The next prime is 13815040718177. The reversal of 13815040718147 is 74181704051831.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13815040718147 - 24 = 13815040718131 is a prime.
It is a super-2 number, since 2×138150407181472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13815040718095 and 13815040718104.
It is not a weakly prime, because it can be changed into another prime (13815040718107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6907520359073 + 6907520359074.
It is an arithmetic number, because the mean of its divisors is an integer number (6907520359074).
Almost surely, 213815040718147 is an apocalyptic number.
13815040718147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13815040718147 is an equidigital number, since it uses as much as digits as its factorization.
13815040718147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 752640, while the sum is 50.
Adding to 13815040718147 its reverse (74181704051831), we get a palindrome (87996744769978).
The spelling of 13815040718147 in words is "thirteen trillion, eight hundred fifteen billion, forty million, seven hundred eighteen thousand, one hundred forty-seven".
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