Base | Representation |
---|---|
bin | 1100100100001001000010… |
… | …0110000011010100110011 |
3 | 1210220201000221101220201121 |
4 | 3021002100212003110303 |
5 | 3302321200410440011 |
6 | 45214313031443111 |
7 | 2624050405401532 |
oct | 311022046032463 |
9 | 53821027356647 |
10 | 13815040718131 |
11 | 4446a20367654 |
12 | 1671545226497 |
13 | 7929a2a394b3 |
14 | 35a919b70319 |
15 | 18e563132e71 |
hex | c9090983533 |
13815040718131 has 2 divisors, whose sum is σ = 13815040718132. Its totient is φ = 13815040718130.
The previous prime is 13815040718107. The next prime is 13815040718147. The reversal of 13815040718131 is 13181704051831.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13815040718131 - 223 = 13815032329523 is a prime.
It is a super-2 number, since 2×138150407181312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13815040715131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6907520359065 + 6907520359066.
It is an arithmetic number, because the mean of its divisors is an integer number (6907520359066).
Almost surely, 213815040718131 is an apocalyptic number.
13815040718131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13815040718131 is an equidigital number, since it uses as much as digits as its factorization.
13815040718131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 43.
Adding to 13815040718131 its reverse (13181704051831), we get a palindrome (26996744769962).
The spelling of 13815040718131 in words is "thirteen trillion, eight hundred fifteen billion, forty million, seven hundred eighteen thousand, one hundred thirty-one".
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