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1381514051 is a prime number
BaseRepresentation
bin101001001011000…
…0011101101000011
310120021120012000002
41102112003231003
510312131422201
6345030350215
746143450521
oct12226035503
93507505002
101381514051
11649912a55
123267bb36b
131902a8548
14d169d311
158144276b
hex52583b43

1381514051 has 2 divisors, whose sum is σ = 1381514052. Its totient is φ = 1381514050.

The previous prime is 1381514047. The next prime is 1381514053. The reversal of 1381514051 is 1504151831.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1381514051 - 22 = 1381514047 is a prime.

It is a super-2 number, since 2×13815140512 = 3817162146220861202, which contains 22 as substring.

Together with 1381514053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1381514053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690757025 + 690757026.

It is an arithmetic number, because the mean of its divisors is an integer number (690757026).

Almost surely, 21381514051 is an apocalyptic number.

1381514051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1381514051 is an equidigital number, since it uses as much as digits as its factorization.

1381514051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 29.

The square root of 1381514051 is about 37168.7240970147. The cubic root of 1381514051 is about 1113.7432940385.

Adding to 1381514051 its reverse (1504151831), we get a palindrome (2885665882).

The spelling of 1381514051 in words is "one billion, three hundred eighty-one million, five hundred fourteen thousand, fifty-one".