Base | Representation |
---|---|
bin | 1100100100101110001010… |
… | …1010010101001100110111 |
3 | 1210221122202112200012200121 |
4 | 3021023202222111030313 |
5 | 3303002103410144411 |
6 | 45223042030352411 |
7 | 2624552400610015 |
oct | 311134252251467 |
9 | 53848675605617 |
10 | 13825007506231 |
11 | 4450175358009 |
12 | 167346705b707 |
13 | 793900898a4c |
14 | 35b1c37298b5 |
15 | 18e948130571 |
hex | c92e2a95337 |
13825007506231 has 2 divisors, whose sum is σ = 13825007506232. Its totient is φ = 13825007506230.
The previous prime is 13825007506159. The next prime is 13825007506283. The reversal of 13825007506231 is 13260570052831.
13825007506231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13825007506231 - 211 = 13825007504183 is a prime.
It is a super-2 number, since 2×138250075062312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13825007536231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6912503753115 + 6912503753116.
It is an arithmetic number, because the mean of its divisors is an integer number (6912503753116).
Almost surely, 213825007506231 is an apocalyptic number.
13825007506231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13825007506231 is an equidigital number, since it uses as much as digits as its factorization.
13825007506231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 13825007506231 in words is "thirteen trillion, eight hundred twenty-five billion, seven million, five hundred six thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •