Base | Representation |
---|---|
bin | 1100100101000110000111… |
… | …0000100010010110000111 |
3 | 1210222021100110202220100202 |
4 | 3021101201300202112013 |
5 | 3303103234302303123 |
6 | 45230023510001115 |
7 | 2625200564013155 |
oct | 311214160422607 |
9 | 53867313686322 |
10 | 13831434806663 |
11 | 44529733aaa51 |
12 | 167475b64619b |
13 | 7943b63443b6 |
14 | 35b6331a83d5 |
15 | 18ebc2520a28 |
hex | c9461c22587 |
13831434806663 has 8 divisors (see below), whose sum is σ = 13849818998400. Its totient is φ = 13813051650048.
The previous prime is 13831434806611. The next prime is 13831434806701. The reversal of 13831434806663 is 36660843413831.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13831434806663 - 28 = 13831434806407 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13831434806599 and 13831434806608.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13831434806263) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28620170 + ... + 29099432.
It is an arithmetic number, because the mean of its divisors is an integer number (1731227374800).
Almost surely, 213831434806663 is an apocalyptic number.
13831434806663 is a deficient number, since it is larger than the sum of its proper divisors (18384191737).
13831434806663 is an equidigital number, since it uses as much as digits as its factorization.
13831434806663 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517561.
The product of its (nonzero) digits is 17915904, while the sum is 56.
The spelling of 13831434806663 in words is "thirteen trillion, eight hundred thirty-one billion, four hundred thirty-four million, eight hundred six thousand, six hundred sixty-three".
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