Base | Representation |
---|---|
bin | 11001110001100001… |
… | …11010010011000001 |
3 | 1022201100020000100212 |
4 | 30320300322103001 |
5 | 211314313411211 |
6 | 10205020123505 |
7 | 666620443655 |
oct | 147060722301 |
9 | 38640200325 |
10 | 13837247681 |
11 | 5960846a94 |
12 | 2822096595 |
13 | 13c699672a |
14 | 953a2ca65 |
15 | 55ebd538b |
hex | 338c3a4c1 |
13837247681 has 2 divisors, whose sum is σ = 13837247682. Its totient is φ = 13837247680.
The previous prime is 13837247621. The next prime is 13837247689. The reversal of 13837247681 is 18674273831.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13051006081 + 786241600 = 114241^2 + 28040^2 .
It is a cyclic number.
It is not a de Polignac number, because 13837247681 - 26 = 13837247617 is a prime.
It is a super-2 number, since 2×138372476812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13837247689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6918623840 + 6918623841.
It is an arithmetic number, because the mean of its divisors is an integer number (6918623841).
Almost surely, 213837247681 is an apocalyptic number.
It is an amenable number.
13837247681 is a deficient number, since it is larger than the sum of its proper divisors (1).
13837247681 is an equidigital number, since it uses as much as digits as its factorization.
13837247681 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1354752, while the sum is 50.
The spelling of 13837247681 in words is "thirteen billion, eight hundred thirty-seven million, two hundred forty-seven thousand, six hundred eighty-one".
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