Base | Representation |
---|---|
bin | 1100100101101111010111… |
… | …1101100100011100100111 |
3 | 1211000022221101221020221111 |
4 | 3021123311331210130213 |
5 | 3303243430330420303 |
6 | 45235054543125451 |
7 | 2626042221461344 |
oct | 311336575443447 |
9 | 54008841836844 |
10 | 13842511185703 |
11 | 4457637766512 |
12 | 1676930ba3887 |
13 | 795460031c35 |
14 | 35bda427b7cb |
15 | 19011eb4ab6d |
hex | c96f5f64727 |
13842511185703 has 2 divisors, whose sum is σ = 13842511185704. Its totient is φ = 13842511185702.
The previous prime is 13842511185697. The next prime is 13842511185733. The reversal of 13842511185703 is 30758111524831.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13842511185703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13842511185733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6921255592851 + 6921255592852.
It is an arithmetic number, because the mean of its divisors is an integer number (6921255592852).
Almost surely, 213842511185703 is an apocalyptic number.
13842511185703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13842511185703 is an equidigital number, since it uses as much as digits as its factorization.
13842511185703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 49.
The spelling of 13842511185703 in words is "thirteen trillion, eight hundred forty-two billion, five hundred eleven million, one hundred eighty-five thousand, seven hundred three".
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