Base | Representation |
---|---|
bin | 11111011110111011000011… |
… | …000110001000001101001111 |
3 | 200011021001220010012212020110 |
4 | 133132323003012020031033 |
5 | 121122100122241231142 |
6 | 1210253402552051103 |
7 | 41110503424632564 |
oct | 3736730306101517 |
9 | 604231803185213 |
10 | 138464428852047 |
11 | 40134486365a21 |
12 | 13643401093a93 |
13 | 5c351a796a16c |
14 | 26299dd75c86b |
15 | 1101b9e39299c |
hex | 7deec318834f |
138464428852047 has 4 divisors (see below), whose sum is σ = 184619238469400. Its totient is φ = 92309619234696.
The previous prime is 138464428851989. The next prime is 138464428852063. The reversal of 138464428852047 is 740258824464831.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 138464428852047 - 231 = 138462281368399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138464428852097) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23077404808672 + ... + 23077404808677.
It is an arithmetic number, because the mean of its divisors is an integer number (46154809617350).
Almost surely, 2138464428852047 is an apocalyptic number.
138464428852047 is a deficient number, since it is larger than the sum of its proper divisors (46154809617353).
138464428852047 is an equidigital number, since it uses as much as digits as its factorization.
138464428852047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46154809617352.
The product of its (nonzero) digits is 330301440, while the sum is 66.
The spelling of 138464428852047 in words is "one hundred thirty-eight trillion, four hundred sixty-four billion, four hundred twenty-eight million, eight hundred fifty-two thousand, forty-seven".
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