Base | Representation |
---|---|
bin | 11001110011100000… |
… | …00110010100011101 |
3 | 1022202111101120100001 |
4 | 30321300012110131 |
5 | 211333033440442 |
6 | 10210411134301 |
7 | 1000211313304 |
oct | 147160062435 |
9 | 38674346301 |
10 | 13853811997 |
11 | 596a130003 |
12 | 2827744391 |
13 | 13ca2460bc |
14 | 955d0143b |
15 | 5613a82b7 |
hex | 339c0651d |
13853811997 has 2 divisors, whose sum is σ = 13853811998. Its totient is φ = 13853811996.
The previous prime is 13853811947. The next prime is 13853812067. The reversal of 13853811997 is 79911835831.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13794737401 + 59074596 = 117451^2 + 7686^2 .
It is a cyclic number.
It is not a de Polignac number, because 13853811997 - 27 = 13853811869 is a prime.
It is a super-2 number, since 2×138538119972 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13853811947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6926905998 + 6926905999.
It is an arithmetic number, because the mean of its divisors is an integer number (6926905999).
Almost surely, 213853811997 is an apocalyptic number.
It is an amenable number.
13853811997 is a deficient number, since it is larger than the sum of its proper divisors (1).
13853811997 is an equidigital number, since it uses as much as digits as its factorization.
13853811997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1632960, while the sum is 55.
The spelling of 13853811997 in words is "thirteen billion, eight hundred fifty-three million, eight hundred eleven thousand, nine hundred ninety-seven".
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