Base | Representation |
---|---|
bin | 1100100110110111000011… |
… | …1101111011110100010101 |
3 | 1211002011121112002111222201 |
4 | 3021231300331323310111 |
5 | 3304102333203420211 |
6 | 45252000251324501 |
7 | 2630323130165134 |
oct | 311556075736425 |
9 | 54064545074881 |
10 | 13861754748181 |
11 | 44648121a885a |
12 | 167a601750731 |
13 | 797208a99bb2 |
14 | 35ccabcd791b |
15 | 1908992970c1 |
hex | c9b70f7bd15 |
13861754748181 has 2 divisors, whose sum is σ = 13861754748182. Its totient is φ = 13861754748180.
The previous prime is 13861754748119. The next prime is 13861754748187. The reversal of 13861754748181 is 18184745716831.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12115683216081 + 1746071532100 = 3480759^2 + 1321390^2 .
It is a cyclic number.
It is not a de Polignac number, because 13861754748181 - 219 = 13861754223893 is a prime.
It is a super-2 number, since 2×138617547481812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13861754748187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6930877374090 + 6930877374091.
It is an arithmetic number, because the mean of its divisors is an integer number (6930877374091).
Almost surely, 213861754748181 is an apocalyptic number.
It is an amenable number.
13861754748181 is a deficient number, since it is larger than the sum of its proper divisors (1).
13861754748181 is an equidigital number, since it uses as much as digits as its factorization.
13861754748181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36126720, while the sum is 64.
The spelling of 13861754748181 in words is "thirteen trillion, eight hundred sixty-one billion, seven hundred fifty-four million, seven hundred forty-eight thousand, one hundred eighty-one".
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