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1387018024817 is a prime number
BaseRepresentation
bin10100001011110000101…
…101110111011101110001
311220121010200010010102012
4110023300231313131301
5140211103103243232
62541104241532305
7202131412453625
oct24136055673561
94817120103365
101387018024817
1149525a574187
121a4991644095
13a0a451a6559
144b1bc413185
152612d5bd9b2
hex142f0b77771

1387018024817 has 2 divisors, whose sum is σ = 1387018024818. Its totient is φ = 1387018024816.

The previous prime is 1387018024807. The next prime is 1387018024913. The reversal of 1387018024817 is 7184208107831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 870817446976 + 516200577841 = 933176^2 + 718471^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1387018024817 is a prime.

It is not a weakly prime, because it can be changed into another prime (1387018024807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 693509012408 + 693509012409.

It is an arithmetic number, because the mean of its divisors is an integer number (693509012409).

Almost surely, 21387018024817 is an apocalyptic number.

It is an amenable number.

1387018024817 is a deficient number, since it is larger than the sum of its proper divisors (1).

1387018024817 is an equidigital number, since it uses as much as digits as its factorization.

1387018024817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 602112, while the sum is 50.

The spelling of 1387018024817 in words is "one trillion, three hundred eighty-seven billion, eighteen million, twenty-four thousand, eight hundred seventeen".