Base | Representation |
---|---|
bin | 1000000100111100001… |
… | …0100000111100011101 |
3 | 111021011202212000202020 |
4 | 2001033002200330131 |
5 | 4233142320402030 |
6 | 143425303450353 |
7 | 13011504101301 |
oct | 2011702407435 |
9 | 437152760666 |
10 | 138765012765 |
11 | 53939260a35 |
12 | 22a881569b9 |
13 | 10115a6a812 |
14 | 6a055d1d01 |
15 | 39225c4510 |
hex | 204f0a0f1d |
138765012765 has 32 divisors (see below), whose sum is σ = 223331230080. Its totient is φ = 73572520704.
The previous prime is 138765012761. The next prime is 138765012773. The reversal of 138765012765 is 567210567831.
It is not a de Polignac number, because 138765012765 - 22 = 138765012761 is a prime.
It is a super-2 number, since 2×1387650127652 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138765012761) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13089447 + ... + 13100043.
It is an arithmetic number, because the mean of its divisors is an integer number (6979100940).
Almost surely, 2138765012765 is an apocalyptic number.
138765012765 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
138765012765 is a deficient number, since it is larger than the sum of its proper divisors (84566217315).
138765012765 is a wasteful number, since it uses less digits than its factorization.
138765012765 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15661.
The product of its (nonzero) digits is 2116800, while the sum is 51.
The spelling of 138765012765 in words is "one hundred thirty-eight billion, seven hundred sixty-five million, twelve thousand, seven hundred sixty-five".
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