Base | Representation |
---|---|
bin | 11111100100011010111001… |
… | …001101111101011100010111 |
3 | 200012121012001001101121101212 |
4 | 133210122321031331130113 |
5 | 121144242331341124444 |
6 | 1211143122505012035 |
7 | 41150006435603342 |
oct | 3744327115753427 |
9 | 605535031347355 |
10 | 138842220254999 |
11 | 4026a7227a7688 |
12 | 136a467678401b |
13 | 5c619c417c101 |
14 | 263dddc1a1459 |
15 | 110b9111a619e |
hex | 7e46b937d717 |
138842220254999 has 2 divisors, whose sum is σ = 138842220255000. Its totient is φ = 138842220254998.
The previous prime is 138842220254939. The next prime is 138842220255119. The reversal of 138842220254999 is 999452022248831.
It is a weak prime.
It is an emirp because it is prime and its reverse (999452022248831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 138842220254999 - 220 = 138842219206423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (138842220254939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69421110127499 + 69421110127500.
It is an arithmetic number, because the mean of its divisors is an integer number (69421110127500).
Almost surely, 2138842220254999 is an apocalyptic number.
138842220254999 is a deficient number, since it is larger than the sum of its proper divisors (1).
138842220254999 is an equidigital number, since it uses as much as digits as its factorization.
138842220254999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 179159040, while the sum is 68.
The spelling of 138842220254999 in words is "one hundred thirty-eight trillion, eight hundred forty-two billion, two hundred twenty million, two hundred fifty-four thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •