139000423 has 2 divisors, whose sum is σ = 139000424. Its totient is φ = 139000422.

The previous prime is 139000391. The next prime is 139000429. The reversal of 139000423 is 324000931.

139000423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 139000423 - 2⁵ = 139000391 is a prime.

It is a super-2 number, since 2×139000423² = 38642235188357858, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 139000394 and 139000403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (139000429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69500211 + 69500212.

It is an arithmetic number, because the mean of its divisors is an integer number (69500212).

Almost surely, 2^139000423 is an apocalyptic number.

139000423 is a deficient number, since it is larger than the sum of its proper divisors (1).

139000423 is an equidigital number, since it uses as much as digits as its factorization.

139000423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

The square root of 139000423 is about 11789.8440617338. The cubic root of 139000423 is about 518.0106722010.

The spelling of 139000423 in words is "one hundred thirty-nine million, four hundred twenty-three", and thus it is an aban number.