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13900433 is a prime number
BaseRepresentation
bin110101000001…
…101010010001
3222011012210212
4311001222101
512024303213
61213533505
7226103021
oct65015221
928135725
1013900433
117934668
1247a4295
132b59011
141bbba81
1513489a8
hexd41a91

13900433 has 2 divisors, whose sum is σ = 13900434. Its totient is φ = 13900432.

The previous prime is 13900429. The next prime is 13900463. The reversal of 13900433 is 33400931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8596624 + 5303809 = 2932^2 + 2303^2 .

It is a cyclic number.

It is not a de Polignac number, because 13900433 - 22 = 13900429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13900399 and 13900408.

It is not a weakly prime, because it can be changed into another prime (13900463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6950216 + 6950217.

It is an arithmetic number, because the mean of its divisors is an integer number (6950217).

Almost surely, 213900433 is an apocalyptic number.

It is an amenable number.

13900433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13900433 is an equidigital number, since it uses as much as digits as its factorization.

13900433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

The square root of 13900433 is about 3728.3284458320. The cubic root of 13900433 is about 240.4415078987.

The spelling of 13900433 in words is "thirteen million, nine hundred thousand, four hundred thirty-three".